log^2(x-1)-log^2(x+1)=3

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Solution for log^2(x-1)-log^2(x+1)=3 equation:


Simplifying
log2(x + -1) + -1log2(x + 1) = 3

Reorder the terms:
g2lo(-1 + x) + -1log2(x + 1) = 3
(-1 * g2lo + x * g2lo) + -1log2(x + 1) = 3
(-1g2lo + g2lox) + -1log2(x + 1) = 3

Reorder the terms:
-1g2lo + g2lox + -1g2lo(1 + x) = 3
-1g2lo + g2lox + (1 * -1g2lo + x * -1g2lo) = 3
-1g2lo + g2lox + (-1g2lo + -1g2lox) = 3

Reorder the terms:
-1g2lo + -1g2lo + g2lox + -1g2lox = 3

Combine like terms: -1g2lo + -1g2lo = -2g2lo
-2g2lo + g2lox + -1g2lox = 3

Combine like terms: g2lox + -1g2lox = 0
-2g2lo + 0 = 3
-2g2lo = 3

Solving
-2g2lo = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '-2lo'.
g2 = -1.5l-1o-1

Simplifying
g2 = -1.5l-1o-1

Combine like terms: -1.5l-1o-1 + 1.5l-1o-1 = 0.0
g2 + 1.5l-1o-1 = 0.0

The solution to this equation could not be determined.

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